number-of-substrings-with-only-1s

number-of-substrings-with-only-1s


Given a binary string s, return the number of substrings with all characters 1's. Since the answer may be too large, return it modulo 109 + 7.



 


Example 1:



Input: s = "0110111"
Output: 9
Explanation: There are 9 substring in total with only 1's characters.
"1" -> 5 times.
"11" -> 3 times.
"111" -> 1 time.


Example 2:



Input: s = "101"
Output: 2
Explanation: Substring "1" is shown 2 times in s.


Example 3:



Input: s = "111111"
Output: 21
Explanation: Each substring contains only 1's characters.


 


Constraints:




  • 1 <= s.length <= 105

  • s[i] is either '0' or '1'.


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