minimum-operations-to-make-array-sum-divisible-by-k

minimum-operations-to-make-array-sum-divisible-by-k


You are given an integer array nums and an integer k. You can perform the following operation any number of times:




  • Select an index i and replace nums[i] with nums[i] - 1.



Return the minimum number of operations required to make the sum of the array divisible by k.



 


Example 1:




Input: nums = [3,9,7], k = 5



Output: 4



Explanation:




  • Perform 4 operations on nums[1] = 9. Now, nums = [3, 5, 7].

  • The sum is 15, which is divisible by 5.




Example 2:




Input: nums = [4,1,3], k = 4



Output: 0



Explanation:




  • The sum is 8, which is already divisible by 4. Hence, no operations are needed.




Example 3:




Input: nums = [3,2], k = 6



Output: 5



Explanation:




  • Perform 3 operations on nums[0] = 3 and 2 operations on nums[1] = 2. Now, nums = [0, 0].

  • The sum is 0, which is divisible by 6.




 


Constraints:




  • 1 <= nums.length <= 1000

  • 1 <= nums[i] <= 1000

  • 1 <= k <= 100


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