minimum-absolute-distance-between-mirror-pairs
You are given an integer array nums.
A mirror pair is a pair of indices (i, j) such that:
0 <= i < j < nums.length, andreverse(nums[i]) == nums[j], wherereverse(x)denotes the integer formed by reversing the digits ofx. Leading zeros are omitted after reversing, for examplereverse(120) = 21.
Return the minimum absolute distance between the indices of any mirror pair. The absolute distance between indices i and j is abs(i - j).
If no mirror pair exists, return -1.
Example 1:
Input: nums = [12,21,45,33,54]
Output: 1
Explanation:
The mirror pairs are:
- (0, 1) since
reverse(nums[0]) = reverse(12) = 21 = nums[1], giving an absolute distanceabs(0 - 1) = 1. - (2, 4) since
reverse(nums[2]) = reverse(45) = 54 = nums[4], giving an absolute distanceabs(2 - 4) = 2.
The minimum absolute distance among all pairs is 1.
Example 2:
Input: nums = [120,21]
Output: 1
Explanation:
There is only one mirror pair (0, 1) since reverse(nums[0]) = reverse(120) = 21 = nums[1].
The minimum absolute distance is 1.
Example 3:
Input: nums = [21,120]
Output: -1
Explanation:
There are no mirror pairs in the array.
Constraints:
1 <= nums.length <= 1051 <= nums[i] <= 109