maximum-number-of-operations-to-move-ones-to-the-end

maximum-number-of-operations-to-move-ones-to-the-end


You are given a binary string s.



You can perform the following operation on the string any number of times:




  • Choose any index i from the string where i + 1 < s.length such that s[i] == '1' and s[i + 1] == '0'.

  • Move the character s[i] to the right until it reaches the end of the string or another '1'. For example, for s = "010010", if we choose i = 1, the resulting string will be s = "000110".



Return the maximum number of operations that you can perform.



 


Example 1:




Input: s = "1001101"



Output: 4



Explanation:



We can perform the following operations:




  • Choose index i = 0. The resulting string is s = "0011101".

  • Choose index i = 4. The resulting string is s = "0011011".

  • Choose index i = 3. The resulting string is s = "0010111".

  • Choose index i = 2. The resulting string is s = "0001111".




Example 2:




Input: s = "00111"



Output: 0




 


Constraints:




  • 1 <= s.length <= 105

  • s[i] is either '0' or '1'.


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