maximum-frequency-of-an-element-after-performing-operations-i

maximum-frequency-of-an-element-after-performing-operations-i


You are given an integer array nums and two integers k and numOperations.



You must perform an operation numOperations times on nums, where in each operation you:




  • Select an index i that was not selected in any previous operations.

  • Add an integer in the range [-k, k] to nums[i].



Return the maximum possible frequency of any element in nums after performing the operations.



 


Example 1:




Input: nums = [1,4,5], k = 1, numOperations = 2



Output: 2



Explanation:



We can achieve a maximum frequency of two by:




  • Adding 0 to nums[1]. nums becomes [1, 4, 5].

  • Adding -1 to nums[2]. nums becomes [1, 4, 4].




Example 2:




Input: nums = [5,11,20,20], k = 5, numOperations = 1



Output: 2



Explanation:



We can achieve a maximum frequency of two by:




  • Adding 0 to nums[1].




 


Constraints:




  • 1 <= nums.length <= 105

  • 1 <= nums[i] <= 105

  • 0 <= k <= 105

  • 0 <= numOperations <= nums.length


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