maximum-difference-between-even-and-odd-frequency-i

You are given a string s consisting of lowercase English letters.

Your task is to find the maximum difference diff = freq(a1) - freq(a2) between the frequency of characters a1 and a2 in the string such that:

• a1 has an odd frequency in the string.


• a2 has an even frequency in the string.

Return this maximum difference.

Example 1:

Input: s = "aaaaabbc"

Output: 3

Explanation:

• The character 'a' has an odd frequency of 5, and 'b' has an even frequency of 2.


• The maximum difference is 5 - 2 = 3.

Example 2:

Input: s = "abcabcab"

Output: 1

Explanation:

• The character 'a' has an odd frequency of 3, and 'c' has an even frequency of 2.


• The maximum difference is 3 - 2 = 1.

Constraints:

• 3 <= s.length <= 100


• s consists only of lowercase English letters.


• s contains at least one character with an odd frequency and one with an even frequency.