maximum-count-of-positive-integer-and-negative-integer

maximum-count-of-positive-integer-and-negative-integer


Given an array nums sorted in non-decreasing order, return the maximum between the number of positive integers and the number of negative integers.




  • In other words, if the number of positive integers in nums is pos and the number of negative integers is neg, then return the maximum of pos and neg.



Note that 0 is neither positive nor negative.



 


Example 1:



Input: nums = [-2,-1,-1,1,2,3]
Output: 3
Explanation: There are 3 positive integers and 3 negative integers. The maximum count among them is 3.


Example 2:



Input: nums = [-3,-2,-1,0,0,1,2]
Output: 3
Explanation: There are 2 positive integers and 3 negative integers. The maximum count among them is 3.


Example 3:



Input: nums = [5,20,66,1314]
Output: 4
Explanation: There are 4 positive integers and 0 negative integers. The maximum count among them is 4.


 


Constraints:




  • 1 <= nums.length <= 2000

  • -2000 <= nums[i] <= 2000

  • nums is sorted in a non-decreasing order.



 


Follow up: Can you solve the problem in O(log(n)) time complexity?


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