evaluate-division

evaluate-division


You are given an array of variable pairs equations and an array of real numbers values, where equations[i] = [Ai, Bi] and values[i] represent the equation Ai / Bi = values[i]. Each Ai or Bi is a string that represents a single variable.



You are also given some queries, where queries[j] = [Cj, Dj] represents the jth query where you must find the answer for Cj / Dj = ?.



Return the answers to all queries. If a single answer cannot be determined, return -1.0.



Note: The input is always valid. You may assume that evaluating the queries will not result in division by zero and that there is no contradiction.



 


Example 1:



Input: equations = [["a","b"],["b","c"]], values = [2.0,3.0], queries = [["a","c"],["b","a"],["a","e"],["a","a"],["x","x"]]
Output: [6.00000,0.50000,-1.00000,1.00000,-1.00000]
Explanation: 
Given: a / b = 2.0, b / c = 3.0
queries are: a / c = ?, b / a = ?, a / e = ?, a / a = ?, x / x = ?
return: [6.0, 0.5, -1.0, 1.0, -1.0 ]


Example 2:



Input: equations = [["a","b"],["b","c"],["bc","cd"]], values = [1.5,2.5,5.0], queries = [["a","c"],["c","b"],["bc","cd"],["cd","bc"]]
Output: [3.75000,0.40000,5.00000,0.20000]


Example 3:



Input: equations = [["a","b"]], values = [0.5], queries = [["a","b"],["b","a"],["a","c"],["x","y"]]
Output: [0.50000,2.00000,-1.00000,-1.00000]


 


Constraints:




  • 1 <= equations.length <= 20

  • equations[i].length == 2

  • 1 <= Ai.length, Bi.length <= 5

  • values.length == equations.length

  • 0.0 < values[i] <= 20.0

  • 1 <= queries.length <= 20

  • queries[i].length == 2

  • 1 <= Cj.length, Dj.length <= 5

  • Ai, Bi, Cj, Dj consist of lower case English letters and digits.


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