construct-uniform-parity-array-i

You are given an array nums1 of n distinct integers.

You want to construct another array nums2 of length n such that the elements in nums2 are either all odd or all even.

For each index i, you must choose exactly one of the following (in any order):

• nums2[i] = nums1[i]


• nums2[i] = nums1[i] - nums1[j], for an index j != i

Return true if it is possible to construct such an array, otherwise, return false.

Example 1:

Input: nums1 = [2,3]

Output: true

Explanation:

• Choose nums2[0] = nums1[0] - nums1[1] = 2 - 3 = -1.


• Choose nums2[1] = nums1[1] = 3.


• nums2 = [-1, 3], and both elements are odd. Thus, the answer is true​​​​​​​.

Example 2:

Input: nums1 = [4,6]

Output: true

Explanation:​​​​​​​

• Choose nums2[0] = nums1[0] = 4.


• Choose nums2[1] = nums1[1] = 6.


• nums2 = [4, 6], and all elements are even. Thus, the answer is true.

Constraints:

• 1 <= n == nums1.length <= 100


• 1 <= nums1[i] <= 100


• nums1 consists of distinct integers.