Training Applied-Algebra Material, Study Applied-Algebra Demo

Training Applied-Algebra Material, Study Applied-Algebra Demo


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WGU Applied-Algebra Exam Syllabus Topics:

Section Weight Objectives Systems of Equations and Inequalities 15% - Applications of systems

- Solving by substitution and elimination

- Graphical solutions

Graphing and Functions 25% - Linear functions and their graphs

- Function notation and evaluation

- Slope and equations of lines

- Coordinate plane and plotting points

Exponents, Radicals, and Quadratic Relationships 15% - Properties of exponents

- Simplifying radical expressions

- Basic quadratic graphs

- Solving quadratic equations

Linear Equations and Inequalities 25% - Solving and graphing inequalities

- Real-world applications

- Solving single-variable equations

Algebraic Expressions and Operations 20% - Simplifying and evaluating expressions

- Order of operations

- Variables, constants, and coefficients

- Operations with polynomials

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100% Pass Quiz Marvelous Applied-Algebra Training WGU Applied Algebra FXO2 PFXP C957 Material

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WGU Applied Algebra FXO2 PFXP C957 Sample Questions (Q105-Q110):

NEW QUESTION # 105

The function P(t) represents the yearly profit, in millions of dollars, for a clothing store since opening. The graph of P(t) is shown.


How should the maximum value be interpreted?

  • A. Approximately 10.5 years after opening, a maximum yearly profit of approximately $2,250,000 was earned.
  • B. Approximately 10.5 years after opening, a maximum yearly profit of approximately $2.25 was earned.
  • C. Approximately 16 years after opening, a maximum yearly profit of approximately $2.25 was earned.
  • D. Approximately 16 years after opening, a maximum yearly profit of approximately $2,250,000 was earned.

Answer: A

Explanation:

The maximum value of a polynomial graph is found at the highest point of the curve. In this problem, P(t) represents yearly profit in millions of dollars, and t represents years since opening. The graph reaches its highest point at approximately t=10.5, so the maximum yearly profit occurs about 10.5 years after opening.

The vertical value at that point is about 2.25, but because the profit is measured in millions of dollars, this means 2.25 million dollars. Converting gives 2.25×1,000,000=2,250,000. Therefore, the correct interpretation must include both the correct time and the correct dollar amount. The correct answer is C.


NEW QUESTION # 106

A vehicle is travelling away from a rest stop. The function

D(t)=48t+23

represents the distance from the vehicle to the rest stop at time t, where t is measured in hours and D is measured in miles.

What is the value of D(1.7)?

  • A. 58.6
  • B. 87.1
  • C. 0
  • D. 104.6

Answer: D

Explanation:

The function is:

D(t)=48t+23

This is a linear function because it has the form:

D(t)=mt+b

where:

48

is the rate of change, and:

23

is the starting distance from the rest stop.

We need to find:

D(1.7)

That means substitute:

t=1.7

into the function.

D(1.7)=48(1.7)+23

First multiply:

48(1.7)=81.6

Now add 23:

D(1.7)=81.6+23

D(1.7)=104.6

So the vehicle is:

104.6 miles

from the rest stop after 1.7 hours.


NEW QUESTION # 107

In the graph showing the number of new customer accounts, the horizontal axis shows the number of weeks since the beginning of winter and the vertical axis shows the number of new customer accounts. More customer accounts are opened during snowy weeks than during weeks without snow.


When was it likely snowy?

  • A. It was likely snowy during only week 1.
  • B. It was likely snowy during weeks 1 and 5.
  • C. It was likely snowy during only week 7.
  • D. It was likely snowy during weeks 7 and 14.

Answer: D

Explanation:

This question asks us to interpret unusually high values on a graph. The problem states that more customer accounts are opened during snowy weeks than during weeks without snow. Therefore, the likely snowy weeks correspond to the peaks on the graph, where the number of new customer accounts is noticeably higher than surrounding weeks. The graph shows clear spikes at approximately week 7 and week 14. These weeks have higher account openings compared with nearby weeks, making them the best evidence of snowy conditions.

Week 1 and week 5 do not match the main peaks shown in the graph. Since the snowy weeks should correspond to the highest customer-account values, the correct answer is D.


NEW QUESTION # 108

The function P(t) represents the yearly profit, in thousands of dollars, for a virtual store since opening. The graph of P(t) is shown.


What is the time at which the store reached the maximum yearly profit?

  • A. Approximately 4.5 years after the store opened
  • B. Approximately 7.5 years after the store opened
  • C. Approximately 2.5 years after the store opened
  • D. Approximately 14 years after the store opened

Answer: A

Explanation:

The maximum value of a graph is the highest output value the function reaches. Since P(t) represents yearly profit, the maximum value occurs where the store earns its greatest yearly profit. The graph is a downward- opening curve, so its highest point is the vertex. To answer the question, we need the t-value of the vertex, not the profit amount. From the graph, the highest point occurs between 4 and 5 years after opening, closest to 4.5 years. This means the virtual store reached its maximum yearly profit approximately 4.5 years after it opened.

The later values decrease after the vertex, so options involving 7.5 or 14 years are not correct. Therefore, the correct answer is B.


NEW QUESTION # 109

The function P(t)represents the daily profit, in hundreds of dollars, for a hardware store since opening. The graph of P(t)is shown.


How should the maximum value be interpreted?

  • A. Approximately 21 years after opening, a maximum daily profit of approximately $2,900was earned.
  • B. Approximately 9 years after opening, a maximum daily profit of approximately $1,270was earned.
  • C. Approximately 21 years after opening, a maximum daily profit of approximately $1,270was earned.
  • D. Approximately 9 years after opening, a maximum daily profit of approximately $2,900was earned.

Answer: D

Explanation:

The graph shows P(t), where:

t= " years since opening "

and

P(t)= " daily profit in hundreds of dollars "

The graph is a downward-opening curve, so its maximum value occurs at the highest point of the graph, also called the vertex.

From the graph, the highest point occurs at approximately:

t=9

So the maximum daily profit happened approximately:

9 " years after opening "

The vertical value at this maximum point is approximately:

P(t)=29

But the graph measures profit in hundreds of dollars, so:

29×100=2900

Therefore, the maximum daily profit was approximately:

$2,900

So the correct interpretation is:

" Approximately 9 years after opening, a maximum daily profit of approximately " $2,900 " was earned. "


NEW QUESTION # 110

......

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