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Is it possible when listing a directory to view numerical unix permissions such as 644 rather than the symbolic output -rw-rw-r--
Jon Winstanley
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miku
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Jean-François Fabre♦
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For creating it as an alias (example below: 'cls' command), use: alias cls="ls -l | awk '{k=0;for(i=0;i<=8;i++)k+=((substr(\$1,i+2,1)~/[rwx]/)*2^(8-i));if(k)printf(\"%0o \",k);print}'" – danger89 Mar 6 '14 at 16:15
I copy and pasted the line from danger89 and found that strangely the output began with %0..o per line, instead of say 755. If anyone else comes across this, the cause appears to be a hidden character between the 0 and o. Once deleted the command is set up nicely. Cheers! – Donna Mar 9 '14 at 17:31
I think there is an calculation issue. After chmod 777 dir your command prints permissions as 767 – Julian F. Weinert Apr 24 '14 at 10:55
As Donna mentions, there is a funny character (or 2) between the 0 and o, also, weirdly it looks like SO is adding it... – nbsp Nov 17 '14 at 19:49
This fails to recognize bits t and s. You should use the 'stat' command to get the file permission information. Calculating it by hand will lead to errors! – Evan Langlois Nov 9 '15 at 6:28
Closest I can think of (keeping it simple enough) is stat, assuming you know which files you're looking for. If you don't, * can find most of them:
It handles sticky, suid and company out of the box:
JB.
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This works great under Linux, I found stat -f '%A %N' * does the same thing on a mac (FreeBSD) – reevesy May 29 '14 at 12:07
I guess the argument is that stat is not ls therefore this is not the correct answer. However, I believe this is the correct answer in context of the desired output. If awk is permitted in a pipe, then find should be permitted where stat is called in -exec; then you can use stat directly without * – javafueled Mar 4 '15 at 14:29
This is much better shorter and 100% working on any system – Kangarooo Mar 24 '16 at 23:15
If you want to use stat to see the rights recursively, under bash, use stat -c '%a %n' * **/*. – Denis Chevalier Aug 11 '17 at 13:37
ghostdog74
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This is a command I can actually remember. Helpful and effective. – Trent Oct 28 '15 at 13:55
This should also have -maxdepth 1 option, otherwise it traverses the whole directory tree. – Ruslan May 23 '17 at 13:26
Also you can use any filename or directoryname instead of * to get a specific result.
Mohd Abdul Mujib
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Didn't work for me. stat: illegal option -- c usage: stat [-FlLnqrsx] [-f format] [-t timefmt] [file ...] – rschwieb Mar 14 '16 at 19:25
works on ubuntu 14.04.. to never have to remember this I've added an alias in my .bashrc: alias xxx="stat -c '%a %n' *" – faeb187 Apr 29 '16 at 1:52
Helpful! How you dig it out the %A which not even shows up in man of stat on Mac? – igonejack Jan 17 '18 at 3:43
It actually is a FreeBSD command, and Mac just happens to be built upon that using it as upper kernel. – Mohd Abdul Mujib Jan 17 '18 at 4:44
If we only use the information presented in man stat on macOS 10.14.4, then the command should be stat -f "%Lp %N" *. %Lp appears to print the same thing as %A. – Cesar Andreu Apr 3 '19 at 7:03
wow, nice awk! But what about suid, sgid and sticky bit?
You have to extend your filter with s and t, otherwise they will not count and you get the wrong result. To calculate the octal number for this special flags, the procedure is the same but the index is at 4 7 and 10. the possible flags for files with execute bit set are ---s--s--t amd for files with no execute bit set are ---S--S--T
user224243
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+1 Thanks! I shortened it to a 1-line alias: alias "lsmod=ls -al|awk '{k=0;s=0;for(i=0;i<=8;i++){;k+=((substr(\$1,i+2,1)~/[rwxst]/)*2^(8-i));};j=4;for(i=4;i<=10;i+=3){;s+=((substr(\$1,i,1)~/[stST]/)*j);j/=2;};if(k){;printf(\"%0o%0o \",s,k);};print;}'" – Jeroen Wiert Pluimers Apr 11 '11 at 12:16
Don't use lsmod as an alias.. that's a known posix command for listing kernel mods. – shadowbq Oct 6 '14 at 18:43
@JeroenWiertPluimers That is giving me a syntax error from awk – Evan Langlois Nov 9 '15 at 6:32
Use this to display the Unix numerical permission values (octal values) and file name.
Use this to display the Unix numerical permission values (octal values) and the folder's sgid and sticky bit, user name of the owner, group name, total size in bytes and file name.
Add %y if you need time of last modification in human-readable format. For more options see stat.
Using an alias is a more efficient way to accomplish what you need and it also includes color. The following displays your results organized by group directories first, display in color, print sizes in human readable format (e.g., 1K 234M 2G) edit your ~/.bashrc and add an alias for your account or globally by editing /etc/profile.d/custom.sh
Typing cls displays your new LS command results.
While you are editing your bashrc or custom.sh include the following alias to see a graphical representation where typing lstree will display your current folder tree structure
Erick Gonzalez
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You don't use ls to get a file's permission information. You use the stat command. It will give you the numerical values you want. The "Unix Way" says that you should invent your own script using ls (or 'echo *') and stat and whatever else you like to give the information in the format you desire.
Evan Langlois
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Building off of the chosen answer and the suggestion to use an alias, I converted it to a function so that passing a directory to list is possible.
Curtis Blackwell
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Doesn't work for some UNIX: ls: ERROR: Illegal option -- H then usage: ls -1ACFLRTabcdfgilmnopqrstux -W[sv] [files] and awk: cmd. line:2: fatal: file '/usr/include' is a directory – kbulgrien Oct 6 '20 at 18:04
Considering the question specifies UNIX, not Linux, use of a stat binary is not necessary. The solution below works on a very old UNIX, though a shell other than sh (i.e. bash) was necessary. It is a derivation of glenn jackman's perl stat solution. It seems like an alternative worth exploring for conciseness.
The alias was developed using information in this answer
The whole answer is a modified version of a solution in this answer
kbulgrien
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