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Asked
5 years, 7 months ago

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5 years, 7 months ago

from my bare understanding: 1. ... give a call to default constructor? No. There is not necessary any default constructor for a class. It simply means that the memory is allocated and all members are initialized with default values. 2. ... final object is returned to...constructor which retruns final object Constructor is not returning anything

– Adrian Shum
Jul 2 '15 at 7:20

How is this memory allocated(object created) that too of a type classB in first place during instantiation

– vrogros
Jul 2 '15 at 7:27

the "class" itself should have such information: It know what fields (hence, how much memory, and how fields aligned) is required for itself, and also knows the memory its parent needs. Conceptually it is how it works. If you need to real implementation detail on how it works then it is out of my knowledge :)

– Adrian Shum
Jul 2 '15 at 7:30

And when I said "the constructor returns" I meant to say that the final object is created using the values given in classB(1,1) constructor sorry if it caused some sort of confusion

– vrogros
Jul 2 '15 at 7:31

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I understand that there are three parts to object creation:
It has to create an object using new operator
and this object must have all the fields related to classB (initialized to default values does this step give a call to default constructor?) this is instantiation
does it mean this step is initialization using java's default constructor?
this object is then passed down the hierarchy giving calls to various constructor in the way to get initialized (which comes under initialization)
and the final obj is created by 'classB(1,1)` constructor whith required Initializations
but how is the object mentioned in instantiation step being created initially with all available fields?
please point out if anything i said is wrong
If the class has no constructor a default constructor is implicitly defined.
Constructors have method name in a stacktrace.
A constructor call does the following:
The second step might be modified slightly if there are instance initializers in the class declaration. See Chapter 8 of the Java Language Specification for details.

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If you have ever used Streams and Optionals in Java, you must have come across lambda expressions and functional interfaces. But how exactly are lambda expressions tied to functional interfaces?
This article will talk about functional programming in Java and how Streams and Optionals make use of functional interfaces.
An interface that has only one abstract method (unimplemented method) can qualify to be a functional interface. It may or may not have other default and static methods.
Lambda expressions or functions are blocks of code that can be assigned to a variable, passed around as an argument or even returned from functions. They are anonymous functions and contains parameters, lambda operator ( -> ) and function body.
Lambda expressions were introduced in Java as a means of supporting functional programming.
As Lambda expressions are anonymous functions , passed around as arguments, we need a way to execute these functions on demand. This is where functional interfaces come into play.
Functional interfaces, having only a single abstract method, accepts the lambda function or a method reference as the implementation for that particular abstract method.
To understand better, let’s see how streams and optionals uses lambda expressions as implementations for the abstract method in functional interfaces.
Streams in Java provide a functional approach to process a collection of objects. Stream.java provides different methods to process list elements, map() , flatMap() , filter() , sorted() etc, each of which takes a functional interface type as an argument.
Let’s consider an example of a LIST of names and Stream on the list to filter out names that contains the letter ‘a’.
The .filter() here is a function to filter out elements from the list that satisfies the specified criteria and the .collect() returns back another list with the filtered elements. Notice that the input passed onto the filter function is a lambda expression. The filter() method in Stream.java has the following structure.
As you can see, filter accepts a Predicate as an argument. So what is a predicate?
A predicate is a functional interface provided in java.util.function package and contains one abstract method, which is, boolean test(T t) .
But how do we get the implementation for test(T t)? What gets executed when predicate.test(t) is called?
Looking back at our stream, when the lambda expression, name -> name.contains("a") , is passed as a predicate to filter(), this lambda expression is treated as an implementation for predicate.test(t) and gets evaluated inside filter method.
This is the reason why functional interfaces support only one abstract method. The lambda expression passed will be compiled to provide an implementation for the only abstract method present in the functional interface. Had there been more than one abstract method, the compiler will not know which method should be implemented with the lambda expression passed.
Optionals in Java also use functional interfaces. Optional.ifPresent() accepts an input of type Consumer which is a functional interface.
Consider an example where lambda expression value -> displayName("user1") will be executed inside name.ifPresent() .
The implementation of Optional.ifPresent() inside Optional.java takes a Consumer as an argument, to which this lambda expression is passed.
Consumer contains only one abstract method accept(t) and its implementation will be the lambda expression passed.
The functional interfaces Predicate , Function , Consumer and Supplier are provided in the java.util.function package along with various other interfaces. The functional interfaces provided in java.util.function maybe enough to cover common scenarios, or we can define our own functional interfaces for our requirements .

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