HOW TO CALCULATE BAR IN CIRCULAR SLAB
जॉर्डनो ג׳ורדנו ጆርዳኖ جوردانو จอร์แดโน่ JORDANO Ιορδάνοςஜார்டானோFind the Reinforcement Details Having the Diameter of 3 m Providing Main Reinforcement 10 mm Diameter and Distributor 8 mm Diameter at Spacing 200 mm and Nominal Cover Is 25 mm.
ANSWER
In Circular Slab Reinforcement Length Is Changed Due To Spacing Of the Reinforcement.
For This Cause Using Pythagoras Theorem to Find Out the Length Of each Reinforcement.
L= Diameter of Slab – Nominal Cover
For Pythagoras Theorem L1= (√R 2 – H 12)2 H 1, H 2, H 3 =Spacing Of
Reinforcement
L2= (√R 2 – H 22)2 R = Radius of Slab (Excluding Nominal Slab)
Same Steps for Other Reinforcements
Example for Circular Slab Reinforcement Calculation
Find the Reinforcement Details Having the Diameter of 3 m Providing
Main Reinforcement 10 mm Diameter and Distributor 8 mm Diameter at Spacing 200 mm and Nominal Cover Is 25 mm
✦ L = 3 – 2 (0.05)
✦ L1 = (√R 2 – H 12) X 2
L1 = (√1.475 2 – 0.2 2)2
✦ L2= (√R 2 – H 22)2
L2= (√1.475 2 – 0.42)2
L3= (√R 2 – H 32) X 2
L3= (√1.475 2 – 0.62) X 2
✦ L4 = (√R 2 – H 42) X 2
L4 = (√1.475 2 – 0.8 2) X 2
✦ L5 = (√1.475 2 – 12) X 2
✦ L6 = (√R 2 – H 62) X 2
L6 = (√1.475 2 – 1.2 2) X 2
✦ L7 = (√R 2 – H 72) X 2
L7 = (√1.475 2 – 1.4 2) X 2
Total Length of Main and Distribution Reinforcements
= L + 2(L1) + 2(L2) + 2(L3) + 2(L4) + 2(L5) + 2(L6) + 2(L7)
= 2.95 + 2(2.92) + 2(2.84) + 2(2.70) + 2(2.48) + 2(2.16) + 2(1.72) + 2(0.93)
Total Weight of 10 Mm Diameter Main Reinforcement
Weight of 10 Mm Bar Per Meter Length = 0.617 Kg /M
Weight = 34.45 X 0.617 = 21.26 Kg
Total Weight of 8 Mm Diameter Main Reinforcement
Weight of 8 Mm Bar Per Meter Length = 0.395 Kg /M
Weight = 34.45 X 0.395
= 13.60 Kg
Total Weight of Reinforcement for This Slab = 21.26 + 13.60