❤️ A certain spring stores $100 \mathrm~J$ of potential ener ❤️

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Solved *Just need help with part C I have included A and B

SOLVED A spring that is compressed by 10 cm stores 100 J of

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Transcribed image text: A certain spring stores 12.1 J of potential energy when it is stretched by 2.90 cm from its equilibrium position Part A How much potential energy would the spring store if it were stretched an additional 2.90 cm? Express your answer with the appropriate units. JO HA ? U = 42.40 J Submit Previous Answers Request Answer *. A certain spring stores 12.1 J of potential energy when it is stretched by 2.25 cm from its equilibrium position. Part A. How much potential energy would the spring store if it were stretched an additional 2.25 cm? Express your answer with the appropriate units. SubmitRequest Answer. Part B. Question: A certain spring stores 121 J of potential energy when it is stretched by 2 45 cm from its equilibrium position Part How far from the equilibrium position would you have to stretch the string to store 242 J of potential energy? Express your answer with the appropriate units, HA to ? Al Value Units Submit PREVIOUS Answers Request. A spring that is compressed by 12.5 cm 12.5 c m stores 3.33 J 3.33 J of potential energy. Determine the spring constant. VIDEO ANSWER: Let'S say we have a spring that has 12.1 joules of energy stored in it and that's when it stretched by a distance of 2.25 centimeters, so part a asks. An ideal spring of negligible mass is 12.00 $\mathrm{cm}$ long when nothing is attached to it. When you hang a 3.15 -kg weight from it, you measure its length to be 13.40 $\mathrm{cm}$ . If you wanted to store 10.0 $\mathrm{J}$ of potential energy in this spring, what would be its total length? Assume that it continues to obey Hooke's law. In the figure, x is the displacement from the equilibrium position. When we pull the spring to a displacement of x as shown in the figure, the work done by the spring is : W = 0 ∫ xm Fdx = -∫kx dx = -k (x m) 2 /2. The work done by pulling force F p is : Fp = k (x m) 2 / 2. The work done by the pulling force F p is in positive as it has. Question: *Just need help with part C I have included A and B with correct answers in case needed! Given: A certain spring stores 11.1 J of potential energy when it is streached by 2.30 cm from its equilibrium position. A. How much potential energy would the spring store if it were stretched additional 2.30 cm?Correct Answer Found: U=. Physics questions and answers. A certain spring stores 11.0 J of potential energy when it is stretched by 2.70 cm from its equilibrium position. Part A How much potential energy would the spring store if it were stretched an additional 2.70 cm? Express your answer with the appropriate units. Part B How much potential energy would it store if it. 24 mai 2018 · Chapter 8 Potential Energy And Conservation Of Energy Q.52P A 15,800-kg truck is moving at 12.0 m/s when it starts down a 6.00° incline in the Canadian Rockies. At the start of the descent the driver notices that the altitude is 1630 m. When she reaches an altitude of 1440 m, her speed is 29.0 m/s. 22 déc. 2024 · The formula for Hooke’s law specifically relates the change in extension of the spring, x , to the restoring force, F , generated in it: F = −kx F = −kx. The extra term, k , is the spring constant. The value of this constant depends on the qualities of the specific spring, and this can be directly derived from the properties of the spring. Given parameters are. k = 200 N/m. x = 0.8 m. The potential energy of a string formula is given by. P.E = 1/2 kx2. P.E = ½ (200 x (0.8)2) P.E = 64 J. Example 2: The spring constant and displacement of a stretched string is 100 N/m and 0.5 m respectively. Determine the potential energy stored in the stretched string. 18 janv. 2024 · Calculate the energy. In our example it will be equal to. U = 0.5 × 80 × 0.1 5 2 = 0.9 J. U = 0.5 \times 80 \times 0.15^2 = 0.9 \ \mathrm J U = 0.5×80 ×0.152 = 0.9 J. You can also type the values directly into the elastic potential energy calculator and save yourself some time :) Potential energy is inherently related to work. Step 2: Place the values in the formula of potential energy. U=1/2 k∆x 2 U=1/2×500×(0.3) 2. Elastic Potential Energy U = 22.5 J. In case you don’t have time to do all of the above steps and want to jump directly to the answer, use the potential energy of a spring calculator above. FAQs How is elastic potential energy calculated? Elastic.