Review
taneesha80/100 = m/ms ---------------------(01)
60/100 = (m-0.1)/ms----------------------(02)
35/100 = mo/ms
From (01) and (02) ,
ms = 0.5
mo = 0.175kg
m = 0.4
(m-0.1) = 0.3kg
Extra vapour mass that should be removed = 0.3-0.175
= 0.125kg
Answer - 03