Lol
Charlie puthhttp://orutamil.com/blog/view/65508XeF4 has b pairs of electrons around Xe while
PP+
4has 4 pairs of electrons around p.
2 d The lone pairs occupy equatorial positions and
the three and the three I atoms occupy top,
middle and bottom positions in the
trigonalbipyramid giving linear structure with
bond angle 180o
3 a
2-pairs of electrons on C: linear Structure.
4 b After shaving three electron pairs with three
oxygen atoms, two electrons are left as non-
bonding electrons on Xe in XeO3 , so only one
lone pair exists on the central atom.
5 c 1. ππΉ3 β
1
2
5 + 3 = 4: π π
3
2. ππ3
β β
1
2
5 + 0 + 1 = 3: π π
2
3. BπΉ3 β
1
2
3 + 3 = 3: π π
2
4. π»3π
β¨ β
1
2
6 + 3 β 1 = 4: π π
3
5. HN3 (π»π¦ππππππ§πππ ππππ) is SP hybriolised
And is linear
Thus iso structural pairs are [NF3,H3π
β¨]
and [Nπ3
β¨, π΅πΉ3
]
6 d
7 c
N β Group =15
P
As β Valence =15
S6 - Electrons
Mcl3, has sp3
hybridized M-element with one
lone pair, lone pair and bond pair repulsion
decreases bond angle. However, *** of
electrons are much farther away from the
central atom than they are in NCl3. Thus lone
pair causes even greater distortion in Pcl3,
Ascl3 and Sbcl3. Thus bond angle decreases
from Ncl3 (maximum) to Sbcl3 (minimum).
8 c a) πΆπ3
2β, ππ3
β Triangular planar
b) πππ4
+ , ππππ4
Tectrahedral
c) ππΉ5
Trigonal bipyramidal
π΅ππΉ5
Square pyramidal
d) π΄ππΉ6
3β , ππΉ6
Octaedrai
9 d Specie
s
Hybrid
isaiton
of Xe
Lone
pXeF4 has b pairs of electrons around Xe while
PP+
4has 4 pairs of electrons around p.
2 d The lone pairs occupy equatorial positions and
the three and the three I atoms occupy top,
middle and bottom positions in the
trigonalbipyramid giving linear structure with
bond angle 180o
3 a
2-pairs of electrons on C: linear Structure.
4 b After shaving three electron pairs with three
oxygen atoms, two electrons are left as non-
bonding electrons on Xe in XeO3 , so only one
lone pair exists on the central atom.
5 c 1. ππΉ3 β
1
2
5 + 3 = 4: π π
3
2. ππ3
β β
1
2
5 + 0 + 1 = 3: π π
2
3. BπΉ3 β
1
2
3 + 3 = 3: π π
2
4. π»3π
β¨ β
1
2
6 + 3 β 1 = 4: π π
3
5. HN3 (π»π¦ππππππ§πππ ππππ) is SP hybriolised
And is linear
Thus iso structural pairs are [NF3,H3π
β¨]
and [Nπ3
β¨, π΅πΉ3
]
6 d
7 c
N β Group =15
P
As β Valence =15
S6 - Electrons
Mcl3, has sp3
hybridized M-element with one
lone pair, lone pair and bond pair repulsion
decreases bond angle. However, *** of
electrons are much farther away from the
central atom than they are in NCl3. Thus lone
pair causes even greater distortion in Pcl3,
Ascl3 and Sbcl3. Thus bond angle decreases
from Ncl3 (maximum) to Sbcl3 (minimum).
8 c a) πΆπ3
2β, ππ3
β Triangular planar
b) πππ4
+ , ππππ4
Tectrahedral
c) ππΉ5
Trigonal bipyramidal
π΅ππΉ5
Square pyramidal
d) π΄ππΉ6
3β , ππΉ6
Octaedrai
9 d Specie
s
Hybrid
isaiton
of Xe
Lone
pMam zoom la login agala mam it shows ....your account is lockedWeb login code. Dear Royβ’, we received a request from your account to log in on my.telegram.org. This is your login code:
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If you didn't request this code by trying to log in on my.telegram.org, simply ignore this message.1. (d) Velamen roots are found in epiphytes.
Pneumatophores are respiratory roots.
2. (b) They give additional support to the stem.
3. (a) In garlic scale leaves store food.
4. (a) In ginger underground stem helps in storage and
perenation.
5. (b) Self explanatory
6. (c) Basipetal succession β old flower on the top.
Acropetal succession β old flower at the base.
Centripetal succession β young flower in the
centre.
7. (a) (9) + 1 condition represent two bundles. One with
9 stamens and other with a single stamen.
8. (a) It forms a thin layer, covering the stored starch.
9. (a) Brassicaceae is characterized by tetramerous
flowers.
10. (c) Position of ovary can not be represented in floral
diagram.
11. (c) Didynamy is seen in Salvia and teradynamy in
mustard.
12. (c) β( )β represents syncarpous condtion
G - inferior ovary
G β half inferior ovary
13. (b) During the formation of leaves and elongation of
stem some cells βleft behindβ from shoot apical
meristem, constitute axillary bud.
14. (d) Primary meristems contribute to the formation of
primary plant body.
15. (b) In aquatic plant like Eichhornia, root caps are
absent.
16. (c) Bast fibre is dead cell.
17. (a) Self explanatory
18. (c) (a) and (d) closed vascular bundle
(b) meristeles are present
19. (c) The companion cells in non- flowering plantsare
replaced by albuminous cells as component of
phloem.
20. (c) Collenchyma generally occurs in layers below the
epidermis in d